Math Component

A cannonball is shot upward from the upper deck of a fort with an initial velocity of 192 feet per second.  The deck is 32 feet above the ground.

Use this formula to solve the problem:  h = -16t²+v₀t+h₀

Quadratic Model:  -16t²+192t+32

1.     How high does the cannonball go? ___608 feet___ (Remember you are looking for a specific part of the vertex.)

2.     How long is the cannonball in the air? __12 seconds_ (Remember you can use the quadratic formula.)

I solved this problem using mostly my graphing calculator. I typed in the function into "y =". Then I found the maximum point in the line using "2ND TRACE". This value is the answer for how high the cannonball went. I found how long the cannon ball was in the air by looking at the table and seeing when the line gets to 32 a second time because the first was when the cannonball was fired so the second is when it lands. The x value is the same as the t or time.